Question: f(x)=x4-3x3+2x2+x-1
Solution:
Simplify the above expression,
Solution:
Solution:
Rewrite radicals as rational exponents,
Solution:
f′(x)=ddxx4-3x3+2x2+x-1
f′(x)=ddxx4- ddx3x3+ ddx2x2+ ddxx- ddx1Applying power rule on each term above,
f′(x)=4x3-3(3x2)+ 2(2x)+1 -0Note that derivative of x is 1 because ddxx=ddxx1=1x0=1, and derivative of any constant is 0 because ddxk=ddxkx0=ddxk(0x-1)=0
Simplify the above expression,
f′(x)=4x3-9x2+4x+1Question: f(x)=5x-5+2x-3+x-1+5
Solution:
f′(x)= ddx(x-5+x-3+x-1+5 )Factor out constants,
f′(x)=ddx 5x-5 - ddx 2x-3 + ddx x-1 + ddx 5
f′(x)=5ddxx-5 -2ddxx-3 + ddx x-1 + ddx 5Apply power rule on each term,
f′(x)=5(-5x-6)-2(-3x-4)+ (-1x-2)+0Simplify the expression,
f′(x)=-25x-6+6x-4-x-2Question: f(x)=√x+√x3+1x110
Solution:
Rewrite radicals as rational exponents,
f(x)=x12+x32+x-110Apply power rule on each term,
f′(x)=(12)x12-1+(32)x32-1+(-110)x-110-1Simplify the expression,
f′(x)=(12)x-12+(32)x12-(110)x-1110
thank for solving
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