Example solutions for factoring a two termed quadratic expression by taking the common factor

  • Example 1:    9x2 + 3x
    3(3x2 + x) . . . Taking 3 as a common factor.
    3x(3x + 1) . . . Taking 'x' as the common factor.
    Answer: 3x(3x + 1)
  • Example 2:    2x2 - 3x
    x(2x - 3) . . . Taking 'x' as the common factor.
    Answer: x(2x - 3)
  • Example 3:    8x2 + 15
    Answer: The given expression is a prime expression. It cannot be factored since no number or variable is common to both terms
  • Example 4:    3ax2 + 8abx
    x(3a + 8ba) . . . 'x' is the common factor
    xa(3 + 8b) . . . 'a' is the common factor
    Answer: xa(3 + 8b)
  • Example 5:    4x2 - 3x
    x(4x - 3) . . . 'x' is the common factor
    Answer: x(4x - 3)
  • Example 6:    √3x2 + 3
    √3(x + √3) . . . '√3' is the common factor
    Answer: √3(x + √3)
  • Example 7:    ax2 + bx
    x(ax + b) . . . 'x' is the common factor
    Answer: x(ax + b)
  • Example 8:    35x2 - 2
    Answer: The given expression is a prime expression. It has no common factor

  • Example 9:    (a + b)x2 + a + b
    (a + b)(x2 + 1) . . . '(a + b)' is the common factor
    Answer: (a + b)(x2 + 1)

    		Example 10:   
    		. . . 'x' is the common factor
    		. . . '1/2' is the common factor
    Answer: 

No comments:

Post a Comment