Graph the following quadratic functions given in the vertex form by getting the
coordinates of their vertices, x-intercepts/points and then joining them by a free hand curve.
Detailed instructions on how to graph quadratic equations in vertex form are given in this
post.

`y = (x - 2)^2 + 3` | Vertex: `(2, 3)` Axis of symmetry: `x = 2` x-intercepts: none | |

`y = 3(x - 4)^2 - 5` | Vertex: `(4, -5)` Axis of symmetry: `x = 4` x-intercepts: `{2.71, 5.29}` | |

`y = (x + 1)^2 + 4` | Vertex: `(-1, 4)` Axis of symmetry: `x = -1` x-intercepts: none | |

`y = (x + 3)^2 - 2` | Vertex: `(-3, -2)` Axis of symmetry: `x = -3` x-intercepts: `{-4.41, 1.59}` | |

`y = (x - 5)^2` | Vertex: `(5, 0)` Axis of symmetry: `x = 5` x-intercepts: `{5, 5}` |

Graph the following quadratic functions in the vertex form include as above. Refer the the advanced solved examples problems for graphing quadratic equations in vertex form in this post in order to solve these problems.

`y = (3x + 4)^2 - 6` | Vertex: `(-4/3, -6)` Axis of symmetry: `x = -4/3` x-intercepts: `{-2.15, -0.52}` | |

`y = x^2 - 7` | Vertex: `(0, -7)` Axis of symmetry: `x = 0` x-intercepts: `{-2.65, 2.65}` | |

`y = 3/4(1/2x + 5/2)^2 - 4/3` | Vertex: `(-5, -4/3)` Axis of symmetry: `x = -5` x-intercepts: `{-2.33, -7.67}` | |

`y = -(x + 5)^2 - 7` | Vertex: `(-5, -7)` Axis of symmetry: `x = -5` x-intercepts: none | |

`y = -1/2(5/4x - 6/5)^2 + 8/7` | Vertex: `(24/25, 8/7)` Axis of symmetry: `x = 24/25` x-intercepts: `{-0.25, 2.17}` |

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