(Answers are below the questions)
Questions:
Answers:
Questions:
 a^{2} + 6a + 8 = 0
 10x^{2} + 3x  4 = 0
 Find the value of (x +4y) : (x + 4y)^{2} + (x + 4y)  90 = 0
 a^{2} + 2a/3 + 1/9 = 0
 12c^{2}  c  6 = 0
 √2x^{2} + x  √2 = 0
 x^{2}  5x + 6 = 0


Answers:
 a = {4, 2}
 x = {4/5, 1/2}
 (x + 4y) = {9, 10}
 a = 1/3
 c = {2/3, 3/4}
 x = {1/√2 , √2}
 x = {2, 3}
 x = {14, 14}
 x = {4/3, 2}
 x = {17/2, 3}
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